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Mathematics 13 Online
OpenStudy (anonymous):

permutations: how many different groups of four letters can be made from the letters A-F (6 letters) if letters can only be used once?

OpenStudy (anonymous):

P(6,6) = 6! / (6 - 6)! = 720

OpenStudy (agent0smith):

6 choices for first letter, 5 for the next, 4 for the next then 3... 6*5*4*3

OpenStudy (agent0smith):

@Rohangrr it should be 6P4 not 6P6 - making a four letter group only.

OpenStudy (anonymous):

@agent0smith i think here the order is not important

OpenStudy (agent0smith):

@julian25 the word permutations is the first word of the question :P But i wondered that too, when it just said "groups"

OpenStudy (anonymous):

yes it is a combination the problem ask form groups so it is the same abcd than bacd

OpenStudy (agent0smith):

@julian25 permutations: how many different groups of four letters can be made from the letters A-F (6 letters) if letters can only be used once? The word permutations seems like a massive hint here...

OpenStudy (anonymous):

i dont know what to answer when u tell me about hints and not about analize deeply the problem

OpenStudy (raden):

the last alternative is look at the choices answer :)

OpenStudy (anonymous):

@soapia is too mch quiet in the contro.

OpenStudy (agent0smith):

It doesn't get much more obvious than having the word permutation at the front of the question. Remove the word permutations, and it may become a combinations problem. As is, there should be no debate over whether this question is permutations or not.

OpenStudy (agent0smith):

The reason it says groups is because they are not words - ABCE etc are not words, they're just groups of letters, and if order did not matter, then the question would not be labelled permutations.

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