What is the dy/dx of 1/x ?

Question

hartnn · Answer

use the standard formula for x^n
1/x = x^(-1)

anonymous · Answer

$$1/x= x^{-1}$$
$$dy/dx x^{-1}=-x^{-2}$$
Bring down the exponent and then subtract one from it :)

christos · Answer

So according to yyou this is wrong? http://screencast.com/t/C1ovmjAgq7b

hartnn · Answer

ofcourse its correct,
you got the result -1/x^2, correct.
just the method used is different

anonymous · Answer

Don't forget that a negative (-) exponent can be removed, and the term flipped. They said 
$$-1/x^{2}$$which equals my answer of 
$$-x^{−2}$$

Raising something to a negative exponent basically just flips it :) And @hartnn is right as well, they did it with the limit definition of a derivative, rather than shortcuts

christos · Answer

I see!! Thanks a lot !!