Given that a = (3,4,0) and a.(a+b)=7, what is the value of a.b?
im not sure what you mean by a=(3,4,0) is that a vector or a set?
It's a vector
distribute, is my thought
(a+b) could be many things, my preference being a+b = <1,1,0> that means b = <-2,-3,0>
a.a + a.b = 7 a.b = 7/(a.a)
- a.a
But @amistre64 aren't there infinitely many solutions for a+b? <1,1,0> is one of them, another would be \[\Large <0,\frac74,0>\] meaning \[\Large b = \left<-3 , -\frac{9}{4},0\right>\]
doesnt matter what a+b actually is, the questions asks to determine a.b with whats given.
oh right... lol I'm sorry, I must have misread it as a+b awkwaaard I must be getting drowsy :3
a.(a+b) 3 , 4 , 0 3+x, 4+y, 0+z ---------------- 9+3x+16+4y a.a 3 4 0 3 4 0 ----- 9+16 a.b 3 4 0 x y z ----- 3x+4y a.(a+b) = a.a+a.b = 7 a.b = 7 - a.a = 7 - 25
Thank You : )
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