somebody help me please
in triangle ABC m<B=12 degrees, m<C=32 degrees and a=32 find the lenth of b to the nearest tenth
@terenzreignz
Yeah, I'm here :)
Let's draw a triangle, okay? (this is definitely not drawn to scale) |dw:1368021498829:dw|
|dw:1368021521851:dw|
yay lol okay ill put up the triangle for the equation that i know how to do
|dw:1368021551574:dw|
|dw:1368021348051:dw|
oh there you go
Now, can you state the law of Sines?
no i dont know the law of sines
Okay... in a triangle, the angles are denoted by capital letters, typically A,B,and C while the sides opposite them, by their respective lowercase letters, a,b,and c Catch me so far?
yes
Okay, the law of Sines is as follows... \[\huge \frac{\sin(A)}{a}=\frac{\sin(B)}{b}=\frac{\sin(C)}{c}\] Or equivalently... \[\huge \frac{a}{\sin(A)}=\frac{b}{\sin(B)}=\frac{c}{\sin(C)}\]
In other words, given any triangle, the ratio between sides and the SINES of the angles opposite them is constant within the triangle.
okay so that can be done with the sine number on top or bottom so after we state the law of sines waht do we do next
Okay, we get back to your triangle...|dw:1368022044717:dw| There is still one missing angle, can you deduce what is the measure of angle A? HINT: Remember that the sum of the measures of the interior angles of a triangle ALWAYS add up to 180 degrees :)
136 degreees
Nicely done :) |dw:1368022116270:dw| Now, the trick to these law of sines thing is to find what I call a "determining pair" Not a very catchy name, but what I mean by a pair is one of these... a and A b and B c and C A determining pair is a pair both of whose values are given... there is such a pair in your triangle, which is it? :)
okay a
Yes, precisely, a and A a = 32 and A = 136 degrees Good. Now we're supposed to find B, correct?
Sorry, we're supposed to find b, correct?
yes
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