Question

:)

Answer 1

Identify the vertex for the graph of y = -2x^2 - 12x + 1.

Answer 2

Vertex:
\[-\frac{b}{2a}\]

Where
\[y=ax^2+bx+c\]

Answer 3

So, a would be -2x^2 b would be -12x and c =1 ? Or do I put this in a certain form?

Answer 4

That will be,
a=-2
b=-12
c=1
You don't include the variables

Answer 5

Oh, right! I completely forgot, sorry. So -12/ -4 is the equation?

Answer 6

Actually, its
\[-\frac{(-12)}{2(-2)}\]

Answer 7

Ohh okay. And now how would I use that to find coordinates on a graph?

Answer 8

\[-\frac{b}{2a}\]
Will give you the x-coordiante of the equation, so you just substitute this value into the equation and get y. Then you'll have x and y

Answer 9

That's the vertex

Answer 10

So b is what I substitute for x, and 2a for y?

Answer 11

a=-2
b=-12
c=1
\[\text{x-coordinate of vetex}=-\frac{b}{2a} \\ \\ \text{x-coordinate of vetex}=-\frac{(-12)}{2(-2)}=-3\]

Answer 12

Then substitute -3 into y=-2x^2-12x+1 to find y

Answer 13

ok, so y would be 55?