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Mathematics 18 Online
OpenStudy (anonymous):

What is the solution of the equation? A. 26 B. 14 C. 38 D. 2

OpenStudy (anonymous):

OpenStudy (jack1):

well: 2^5 =32 so firstly move the 3 to the other side: \[2^{5} \sqrt{\left( x+6 \right)^{3}} +3 = 19\]

OpenStudy (jack1):

becomes 2^5 sqrt (x+6)^3 = 19 - 3 2^5 sqrt (x+6)^3 = 16 32 sqrt (x+6)^3 = 16 sqrt (x+6)^3 = 16/32 sqrt (x+6)^3 = 0.5 (x+6)^3 = (0.5)^2

OpenStudy (jack1):

you following ok so far?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

is it D?

OpenStudy (jack1):

cool, so: (x+6)^3 = (0.5)^2 (x+6)^3 = 0.25 x+6 = cube root of 0.25 x +6 = 0.6299 x = 0.6299 - 6 = -5.37 ish so none of the above... hmm... does your initial equation match my first post?

OpenStudy (anonymous):

ugh you lost me

OpenStudy (jack1):

2^5 sqrt (x+6)^3 + 3= 19 is this equation right?

OpenStudy (jack1):

or is it \[2 \times \sqrt[5]{(x+6)^{3}} +3 = 19\]

OpenStudy (jack1):

because there's a huge difference there

OpenStudy (anonymous):

Its not D

OpenStudy (anonymous):

It's A, 26. He meant 2*

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