Question

is the derivative of 1/1+x^2
= 1=x^2-2x/(1+x^2)^2 ??

Answer 1

= 1+x^2-2x/(1+x^2)^2

Answer 2

or is the dervivate of 1 = 0?

Answer 3

is the problem
\[ \frac{1}{(1+x^2)} \]?

Answer 4

yes

Answer 5

how do you do the squared like that?

Answer 6

i think its -2x/(1+x^2)^2

Answer 7

if so, you could write it like this
\[ (1+x^2)^{-1} \]

this is in the form
u^n
and
\[ \frac{d}{dx} u^n = n\ u^{n-1} \frac{du}{dx} \]

Answer 8

how do you do the squared like that?

what do you mean? how to type it in ? use the equation editor.

Answer 9

\[x^2\] wow, i i had no idead that was there, lol

Answer 10

i think its -2x/(1+x^2)^2

yes, that is correct.

with u= 1+x^2
we first do -1* (1+x^2) ^ (-1 -1)
then we do du/dx = d/dx (1+x^2) = d/dx 1 + d/dx x^2 = 0+2x = 2x

putting it together

-2x/(1+x^2)^2

Answer 11

thank you, thats what i thought it was, just making sure!

Answer 12

"\[" x^2 "\]"

without the quotes " will also do the job.

if you see an expression that you want to know how to type in
right click on the equation and you get a menu. Select "show math as", then select
Tex commands. you will see the tex expression that creates it.
you can cut and paste it into the input window
put it between \ [ and \ ] (no spaces between slash and brackets)