tanA + SecA - 1/tanA - SecA +1 = 1+ SinA/CosA
Solve using trigonometrical functions and componendo dividendo......solve fast....plz its urgent....
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OpenStudy (anonymous):
\[\frac{ \tan A+\sec A-1 }{ \tan A-\sec A+1 } = \frac{ 1+\sin A }{ \cos A }\]
OpenStudy (anonymous):
Prove this....
OpenStudy (anonymous):
Prove that the Left hand side is equal to the right hand side.... Using functions, ratios , identities and componendo - dividendo.......Solve fast its really urgent....
OpenStudy (anonymous):
@Loser66 Alright.....no problem....but i hope not more than 30 mins.....
OpenStudy (loser66):
@amistre64
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OpenStudy (loser66):
sorry friend, I am useless, cannot help. I asked someone for help. You have to wait for them
OpenStudy (anonymous):
@Loser66 alright will wait...
OpenStudy (anonymous):
@chmvijay
OpenStudy (chmvijay):
try to convert all in sin and cos :) ans solve the simple maths
OpenStudy (anonymous):
i did that i got SinA +1-cosA/ SinA-1+Cos A plz tell me how to apply the componendo dividendo here....@chmvijay
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OpenStudy (anonymous):
@chmvijay
OpenStudy (chmvijay):
wait let me try wt is sec = i /cos A is it
and tan A= sin A / cos a right
OpenStudy (anonymous):
yup @chmvijay
OpenStudy (chmvijay):
yaa ur right did you check the question once again
OpenStudy (loser66):
Can I go from RHS? if I can, I think I got the answer
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