tanA + SecA - 1/tanA - SecA +1 = 1+ SinA/CosA Solve using trigonometrical functions and componendo dividendo......solve fast....plz its urgent....
\[\frac{ \tan A+\sec A-1 }{ \tan A-\sec A+1 } = \frac{ 1+\sin A }{ \cos A }\]
Prove this....
Prove that the Left hand side is equal to the right hand side.... Using functions, ratios , identities and componendo - dividendo.......Solve fast its really urgent....
@Loser66 Alright.....no problem....but i hope not more than 30 mins.....
@amistre64
sorry friend, I am useless, cannot help. I asked someone for help. You have to wait for them
@Loser66 alright will wait...
@chmvijay
try to convert all in sin and cos :) ans solve the simple maths
i did that i got SinA +1-cosA/ SinA-1+Cos A plz tell me how to apply the componendo dividendo here....@chmvijay
@chmvijay
wait let me try wt is sec = i /cos A is it and tan A= sin A / cos a right
yup @chmvijay
yaa ur right did you check the question once again
Can I go from RHS? if I can, I think I got the answer
ya u can @Loser66
yaaa try @Loser66 you may good idea :)
ok
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