can someone help me with pre calc?
Whatis the first step to prove that Ssubn=> 2+4+6+...+2n=n(n+1) Verify that S sub n is valid for n=1 Assume that S sub n is valid for n=k Show that S subn is valid for n=k Prove that S sub n is valid for n=k+1
@KeganMoore
woah... @hope_nicole <--- taking pre calc i think 0.o
she isn't on.... @KeganMoore
use the series arthmetic formula Sn = n/2 (2a1 + (n-1)d)
im not good in pre cal...and she said she would brb
with a1 is the first term (known a1 = 2) and d is difference each term, we get d = a2-a1 = 4-2 = 2
now, apply them into the formula above
Sn = n/2 (2a1 + (n-1)d) Sn = n/2 (2*2 + (n-1)2) Sn = ... simplify
@RadEn that lost me
it's not solving the equation.... @RadEn
i know, can u simplify the equation i said above ?
no it made no sense to me i'm doin' terrible in this class
oh i see... u want proving by induction, right sorry, didnt read it :)
it's fine that's what I thought lol thanks
this site might useful :) read here : http://www.basic-mathematics.com/proof-by-mathematical-induction.html
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