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OpenStudy (anonymous):
the neutral atom that has the same electron configuration as 1s22s22p6.
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sam (.sam.):
How many electrons are in \(1s^22s^22p^6\)?
OpenStudy (anoop27):
this configuration does not means that it is a neutral atom configuration
OpenStudy (anoop27):
Reason-if an atom loses a electron and acquired this configuration then overall charge on it is +ve (Cation).
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