If the area of triangle ADE is 60 square units, what is the area of the trapezoid BCED?
\[\frac{ A _{1} }{ A _{2} } = \left( \frac{ l _{1} }{ l _{2} } \right)^{2}\] you have area A1 and L1 and L2 length given..
60/x=7/4 X=15
u also have to square 7/4 too
im confused
umm well u have to plug in the values in the formula i wrote.. in frmula L1 and L2 are in braket which is squared.
19.59 ?
yeah.
but thats not one of the answer .. that why im confused A) 11.02 B)48.98 C)24.98 D)53.84
O.o how can i miss.
this formula is for similar figure if u put 4 in denominator its finding for trapeziod which is not similar to a triangle right?
right
ok so u cant pick 4 as 4 is side of trapeziod not the smaller triangle so u would have to pick 3 instead of 4... that will give u the area for smaller triangle.
so it would be 60/x=7/3 x=135 or x=25.71
135 is when 7/3 is squared
noo.. (7/3)^2 .. u forgot to square it
x=11.02?
yeah right ... well this is the area f small triangle.. you have the area for larger one too.. so larger - smaller gives u the area for trapezoid.
so 60-11.02=48.98 so 48.98 is the answer right !?
yeah i think it's right.
okay thank you ! :D
you're most welcome. :)
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