Question

.

Answer 1

leave as is? or use a calculator?

Answer 2

Well instantly we can remove the squared root of 3 which is

1.73205080757

then 6/5= 1.2
Subtract and you get

0.53205080757

Answer 3

Is it
\[\huge \frac{6}{5^{-\sqrt{3}}}?\]

Answer 4

If you multiply by \(5^{\sqrt{3}}\) top and bottom you'll cancel out the denominator
\[\huge \frac{6}{5^{-\sqrt{3}}} \times \frac{5^{\sqrt{3}}}{5^{\sqrt{3}}}\]
\[\huge \frac{6(5^{\sqrt{3}})}{5^{-\sqrt{3}}5^{\sqrt{3}}} \\ \\ \huge \frac{6(5^{\sqrt{3}})}{1}\]

Answer 5

Note:
\[\huge 5^{0}=1\]

Answer 6

Which step you got confused?

Answer 7

Here\[ \huge \frac{6(5^{\sqrt{3}})}{5^{-\sqrt{3}}5^{\sqrt{3}}} \\ \large \text{\to here?} \\ \huge \frac{6(5^{\sqrt{3}})}{1}\]

Answer 8

Law of indices,
\[\huge m^n \times m^p=m^{n+p}\]

Answer 9

So from denominator, we get
\[\Large 5^{-\sqrt3}5^{\sqrt3} =5^{-\sqrt{3}+\sqrt{3}}=5^0=1\]