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what is the exact value of sin^2(13pi/5)+cos^2(13pi/5) and explain
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There's a trigonometry identity that sin^2(x)+cos^2(x)=1, hence if x=13pi/5; sin^2(13pi/5)+cos^2(13pi/5)=1
One way to see this is with a right triangle with hypotenuse one: |dw:1368057614955:dw|
thanks . can you also help me with 2cos^2(pi/8)-1
OK, \[\sin^{2}(x)+\cos^{2}(x)=1\] double \[2\sin^{2}(x)+2\cos^{2}(x)=2\] subtract 1 from each side \[2\sin^{2}(x)+2\cos^{2}(x)-1=1\] Now do you see your equation in the middle? Simplify for your answer.
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