Write the equation of a circle with a center at (-5, -1) and a radius of 5
Answers:

(x + 5)2 + (y + 1)2 = 5

(x + 5)2 + (y + 1)2 = 25

(x – 5)2 + (y – 1)2 = 25

(x – 5)2 + (y – 1)2 = 5

Question

Write the equation of a circle with a center at (-5, -1) and a radius of 5
Answers:

	
(x + 5)2 + (y + 1)2 = 5
	
(x + 5)2 + (y + 1)2 = 25
	
(x – 5)2 + (y – 1)2 = 25
	
(x – 5)2 + (y – 1)2 = 5

jim_thompson5910 · Answer

Hint: 

The general equation of a circle (x-h)^2+(y-k)^2=r^2

has

center: (h,k)

radius:  r

anonymous · Answer

Help explain please @jim_thompson5910

jim_thompson5910 · Answer

so for example, (x – 5)^2 + (y – 1)^2 = 25 is in the form (x-h)^2+(y-k)^2=r^2

where

h = 5
k = 1
r = 5

So we can say

Center: (5,1)

Radius: 5

anonymous · Answer

Oh ok Thank You!

anonymous · Answer

I know its the same thing but I was also having trouble with this one as well @jim_thompson5910

anonymous · Answer

Write the equation of a circle with a center at (1, 2) and a radius of 1.3.

jim_thompson5910 · Answer

this time

h = 1
k = 2
r = 1.3

plug them into (x-h)^2+(y-k)^2=r^2 to get your answer

anonymous · Answer

ok

anonymous · Answer

what do you plug in for x and y @jim_thompson5910

jim_thompson5910 · Answer

you leave them as they are