Question

how many liters of 4 M SOLUTION CAN BE MADE USING 100 GRAMS OF LITHIUM BROMIDE??

Answer 1

n=cv

where:
n=amount of substance (mol)
c=concentration (M)
v=volume (litres)

and n=m/M

where:
n=amount of substance (mol)
m=mass (g)
M=molar mass (g/mol)

Answer 2

LiBr
n=m/M
n=100/(6.9+79.9)
n=1.15 mol

n=cv
1.15=4v
v=0.288L

\[\therefore\]you can make 0.288 L of 4M solution using 100g of lithium bromide