Question

x^2-2x-3 =(x-2)(x-1)?
is this correct?

Answer 1

(x-2)(x-1) =x^2 -3x +2
so its wrong

Answer 2

thats righttttttttttttttttt!!!!!!!!!!!! therefore its PRIME! DUH!!!!

Answer 3

The end numbers will add to the coefficient of the middle term and multiply to the last term

Answer 4

I was adding the 2 and 1 with 3 instead of multiplying it

Answer 5

-3x1=-3
-3+1=-2

Answer 6

x^2-2x-3 = (x-3)(x+1)

Answer 7

I was doing it backwards.

Answer 8

yep

Answer 9

the factors of 3 are 1 and 3. The middle term is negative so the bigger factor is negative and the end term is negative so they have to have opposite signs. That's how I always thought about it at least

Answer 10

so its prime, because it cant be factored. am i right?

Answer 11

no wait... it can be! x^2-2x-3 = (x-3)(x+1) ??

Answer 12

Yeppers :)

Answer 13

i got x^2-3+2