Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.).
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.

Question

Write an inequality to represent the problem (1 pt.) and then solve the inequality by writing the pairs which solve it (1 pt.).
Find all sets of two consecutive positive odd integers whose sum is less than or equal to 18.

anonymous · Answer

if you call the positive integers $m$ and $n$ then there sum is $m+n$

anonymous · Answer

and if the sum is less than or equal to 18, then you can write 
$$m+n\leq 18$$

anonymous · Answer

Yeah...

anonymous · Answer

Sorry, my internet is slow.

anonymous · Answer

i think the site slowed up for a moment
i had to log out and back in

anonymous · Answer

So it would be like,  $$1 + 3 \le 18$$ right? Ohh.

anonymous · Answer

that would be one solution, yes

anonymous · Answer

Then the next would be $$5 + 7 \le 18$$ right?

anonymous · Answer

sure
 there are lots

anonymous · Answer

Yeah, I got it now. Thank you so much!

anonymous · Answer

oh i did not read carefully!!

anonymous · Answer

Hm?

anonymous · Answer

Okay then....

anonymous · Answer

the inequality should be $n+n+1\leq 18$ or $2n+1\leq 18$

anonymous · Answer

but the solutions are still the same
the pairs can be 1,3 or 3,5 or 5,7 or 7,9

anonymous · Answer

So, $$1 + 3 + 1 \le 18$$ instead?

anonymous · Answer

no the solution is still pairs of numbers

anonymous · Answer

like you were writing above
i think i wrote a complete list

anonymous · Answer

Oh, but the inequality would be what you said before, n+n+1≤18 or 2n+1≤18?

anonymous · Answer

So my answer would be like this,
Inequality:

$$n+n+1 \le 18$$

The solutions would be {(1,3),(5,7),(7,9)}

Correct?