write the piecewise function
\[-\left| \frac{ 1 }{ 2 }x+1 \right|\]
Vertex is =2
i mean -2
So you now where the graph changed direction. So what would the equation of the line be if x < -2
The part where I am stuck at is whether it is \[-\left| -\left( \frac{ 1 }{ 2 }x+1 \right) \right|\] or \[\left| -\frac{ 1 }{ 2 }x+1 \right|\]
I don't know how to write it.... do I add the negative at the beginning?
For the piecewise you're going to take away the absolute value sign
and the negative sign in front?
It will have -(x/2 + 1) You just have to determine if that is when x >-2 or x<-2
Oh I see... so the -1 before the absolute value doesn't matter in piecewise function...
Well it does in determining what the function looks like. And what the function looks like is how you'll know how to piece together your piecewise |dw:1368066817265:dw|
Your piecewise is going to say when x<= -2 the equation of that line is _____ and when x > -2 the graph of that line is going to be _____ We know that we're dealing with (x/2 + 1) and -(x/2 + 1) we just have to figure out which is which
|dw:1368067002009:dw|
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