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Mathematics 16 Online
OpenStudy (anonymous):

write the piecewise function

OpenStudy (anonymous):

\[-\left| \frac{ 1 }{ 2 }x+1 \right|\]

OpenStudy (anonymous):

Vertex is =2

OpenStudy (anonymous):

i mean -2

OpenStudy (hunus):

So you now where the graph changed direction. So what would the equation of the line be if x < -2

OpenStudy (anonymous):

The part where I am stuck at is whether it is \[-\left| -\left( \frac{ 1 }{ 2 }x+1 \right) \right|\] or \[\left| -\frac{ 1 }{ 2 }x+1 \right|\]

OpenStudy (anonymous):

I don't know how to write it.... do I add the negative at the beginning?

OpenStudy (hunus):

For the piecewise you're going to take away the absolute value sign

OpenStudy (anonymous):

and the negative sign in front?

OpenStudy (hunus):

It will have -(x/2 + 1) You just have to determine if that is when x >-2 or x<-2

OpenStudy (anonymous):

Oh I see... so the -1 before the absolute value doesn't matter in piecewise function...

OpenStudy (hunus):

Well it does in determining what the function looks like. And what the function looks like is how you'll know how to piece together your piecewise |dw:1368066817265:dw|

OpenStudy (hunus):

Your piecewise is going to say when x<= -2 the equation of that line is _____ and when x > -2 the graph of that line is going to be _____ We know that we're dealing with (x/2 + 1) and -(x/2 + 1) we just have to figure out which is which

OpenStudy (anonymous):

|dw:1368067002009:dw|

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