Can you help me solve this please? http://screencast.com/t/ItHTxZTWBE I know its simple. But if I see how you do it I will do much harder ones
there are a couple ways to do it
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Can you tell me the one that goes somehow like f(x)-f(y) ??
ohh I didnt know about this graph
one way is to interpret the integral as the area under the "curve" \(y=0\) from \(x=0\) to \(x=3\) geometry tells you it is the area of the above triangle, base is 3, height is 3, area is \(\frac{9}{2}\)
the other way is to find the "anti derivative" of \(x\) which is \(\frac{x^2}{2}\) then evaluate that at 3, and at 0, and subtract
i.e. say \[F(x)=\frac{x^2}{2}\] so \[\int_0^3xdx=F(3)-F(0)=\frac{3^2}{2}-\frac{0^2}{2}=\frac{9}{2}\]
i think you wanted the second way
I get it! Thanks a lot for the help! :)
yea!
yw
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