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Mathematics 6 Online
OpenStudy (christos):

What is the derivative of f(x)=cos(x)sin(x) ?

sam (.sam.):

What's your thought?

OpenStudy (anonymous):

\[cosx \frac{ d }{ dx } sinx + sinx \frac{ d }{ dx }cosx\]

OpenStudy (anonymous):

sin(2x) = 2cos(x)sin(x) so, cos(x)sin(x) = \(\frac{sin2x}{2}\) Therefore, \[\frac{d}{dx} cos(x)sin(x)\]\[=\frac{d}{dx} \frac{sin(2x)}{2}\]\[=...\]

OpenStudy (anonymous):

^ both ways are actually correct because they are equal! Something cool to think about

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