Help! I give medals:)Pic attached If the ratio of the surface areas of two similar solids is 9:25,the what is the ratio of their volums?Show work
@TuringTest @Callisto @tanvidais13 @ritez do u thinkone of u could hlpe me out :)
@phi @sriramkumar @Meepi do u think one of u could help me out?
post your work and i'll be helping you. I don't have much free time now. Give me the equations of how to calculate the surface area of a cylinder, a sphere and a cone.
area of a cylinder is 2pir^2+2pirh area of a cone is pir^2+pirl
you'll notice that all those equations will depend on the radius. You have the final value of the surface area so now you must solve the equation in order to find radius. After having the radius just use it to calculate the volume. volume of half a sphere = (4/8)*pi*r^3 volume of the cylinder = (pi*r^2)*h volume of the cone = (1/3)*pi*r^2
OK thanks :)
could u show me who i would sove her r reall quick
oooops, sorry. I just found a better way. Give me 1 min to work it out
OK
The ratio of the surface areas is equal to the square of the ratio of their corresponding linear measures (9/25) = (a/b)^2 The ratio of the volumes is equal to the cube of the ratio of their corresponding linear measures (v1/v2) = (a/b)^3 solving: \[\sqrt{\frac{ 9 }{ 25 }} = \frac{ a }{ b } \] \[\sqrt[3]{\frac{ v1 }{ v2 }} = \frac{ a }{ b }\] now: \[\sqrt{\frac{ 9 }{ 25 }} = \sqrt[3]{\frac{ v1 }{ v2 }} \] so: \[(\sqrt{\frac{ 9 }{ 25 }})^{3} = \frac{ v1 }{ v2 }\] here you have
alright thanks :)
v1/v2 = 27/125
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