Question

***Answer for a medal please***

Two hockey pucks on an ice rink are held together with a compressed spring between them. The pucks are released and the spring pushes them in opposite directions. One puck of mass 0.5 kg moves at 8 m/s. Calculate the speed of the other puck of mass 2 kg.

_________ m/s

-2
+2
-4
+4

Answer 1

@raghuvarenya???

Answer 2

or somebody who is capable of answering...

Answer 3

use law of conversation of Momentum;
\[m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2 \]

Answer 4

can you help me plug the stuff in and i can solve it from there....

Answer 5

where the m1 and m2 is the mass of two objects.
u1 and u2 are the initial velocity of hockey pucks
v1 and v2 are the final velocity of hockey pucks

Answer 6

Thank you!

Answer 7

wait im still having a hard time plugging the stuff into the equation... @MrSensitive

Answer 8

try to rearrange the equation

Answer 9

i did... m1=0.5 thats all i have...

Answer 10

m2 = 2kg
the initial velocity of both pucks are 0
the v1=8m/s and all u have to do is find v2

Answer 11

do i add and subtract to find v2?

Answer 12

0 = 4 - 2v
-4 = -2v
v= +2m/s

Answer 13

great! now i solve right?

Answer 14

:)

Answer 15

the answer +2?

Answer 16

yes

Answer 17

but don't relay on me though

Answer 18

ok thanks for the help though!