Question

Find
P(A/B) if P(A) = 0.4,P(B) = 0.8 andP(B/A) = 0.6

Answer 1

@mikaela19900630 @noided

Answer 2

Do you know formula for P(A/B) ??

Answer 3

No Sir, How to do it ?

Answer 4

Friend my Friend..

Answer 5

I am not sure but it is I think:
\[P(A/B) = \frac{A \cap B}{P(B)}\]

Answer 6

ok

Answer 7

Are you trying to find P(A/B)?

Answer 8

ok I got how to do . Thanks

Answer 9

If P(A) = 0.4 .P(B) =0.8 P(B/A) =0.6.Find P(A/B)?

_____________________________________________________________________

By P(A), P(B), and P(B/A), we can find P(A^B), ie. A intersection B, coz P(B/A)=P(A^B)/P(A).
And then substituting P(A^B) in P(A/B), ie. P(A/B)=P(A^B)/P(B).

In your sum,
Let, P(A^B)=x,

Now, 0.6=x/0.4
So, x=0.24.

So, P(A^B)=0.24.

And, therefore, P(A/B)=0.24/0.8,
ie. 0.3.

Therefore, P(A/B)=0.3.

Answer 10

Its kinda like this.

Answer 11

\[P(A/B) = \frac{P(A \cap B)}{P(B)}\]

Answer 12

Ok Thanks again

Answer 13

\[P(B/A) = \frac{P(A \cap B)}{P(A)}\]

Just divide them now..

Answer 14

By taking ratio you get:

\[\frac{P(A/B)}{P(B/A)} = \frac{P(A)}{P(B)}\]

Now find what you want to find from this..

Answer 15

ok Thanks @waterineyes