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Chemistry
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OpenStudy (anonymous):
Please help! Will become fan.
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OpenStudy (anonymous):
OpenStudy (anonymous):
@thomaster
OpenStudy (aaronq):
convert grams to moles, divide each by it's respective stoichiometric coefficient.
then percent yield = (NaCN/NaAu..) x100%
OpenStudy (anonymous):
wait one second, will you walk it through with me please. I would appreciate it.
OpenStudy (anonymous):
@aaronq
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OpenStudy (aaronq):
do it and ill correct you if you're wrong
OpenStudy (aaronq):
post each step though
OpenStudy (anonymous):
ALRIGHT, first covert 3.00 grams of NaCN to moles = 49? @aaronq
OpenStudy (aaronq):
moles = mass/ molar mass
OpenStudy (anonymous):
3.00/ 49?
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OpenStudy (anonymous):
0.06 moles?
OpenStudy (aaronq):
if 49 g/mol is the molar mass then yes
OpenStudy (anonymous):
yes it is, I added the molecular mass of NA then of C then of N & got 49?
OpenStudy (aaronq):
okay good stuff.
OpenStudy (aaronq):
do the same for NaAu(CN)2
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OpenStudy (anonymous):
next step?
OpenStudy (anonymous):
I got 346 for the molecular mass of NaAu(CN)
do I times that by 2? then 10 divided by that answer? @aaronq
OpenStudy (aaronq):
you're finding the moles of NaAu(CN)2 first
moles=mass/molar mass
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