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Chemistry 15 Online
OpenStudy (anonymous):

Please help! Will become fan.

OpenStudy (anonymous):

OpenStudy (anonymous):

@thomaster

OpenStudy (aaronq):

convert grams to moles, divide each by it's respective stoichiometric coefficient. then percent yield = (NaCN/NaAu..) x100%

OpenStudy (anonymous):

wait one second, will you walk it through with me please. I would appreciate it.

OpenStudy (anonymous):

@aaronq

OpenStudy (aaronq):

do it and ill correct you if you're wrong

OpenStudy (aaronq):

post each step though

OpenStudy (anonymous):

ALRIGHT, first covert 3.00 grams of NaCN to moles = 49? @aaronq

OpenStudy (aaronq):

moles = mass/ molar mass

OpenStudy (anonymous):

3.00/ 49?

OpenStudy (anonymous):

0.06 moles?

OpenStudy (aaronq):

if 49 g/mol is the molar mass then yes

OpenStudy (anonymous):

yes it is, I added the molecular mass of NA then of C then of N & got 49?

OpenStudy (aaronq):

okay good stuff.

OpenStudy (aaronq):

do the same for NaAu(CN)2

OpenStudy (anonymous):

next step?

OpenStudy (anonymous):

I got 346 for the molecular mass of NaAu(CN) do I times that by 2? then 10 divided by that answer? @aaronq

OpenStudy (aaronq):

you're finding the moles of NaAu(CN)2 first moles=mass/molar mass

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