How much heat is absorbed by 15.5 g of water when its temperature is increased from 20.0°C to 50.0°C? The specific heat of water is 4.184 J/(g°C).

Question

aaronq · Answer

q=mC(T2-T1)

anonymous · Answer

could you explain that further? lol so it would be q=15.5(20-50)?

aaronq · Answer

close, 
m=mass, 15.5 g
C=specific heat capacity 4.184 J/(g°C)
T2= final temp, so 50
T1= initial temp so 20

anonymous · Answer

okay so then i would do it this way: q=15.5*4.184(50-20) then the answer would be: 1945.5? lol