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Chemistry 16 Online
OpenStudy (sup_open~study):

For a solution with a hydrogen ion concentration of 3.48x10^-8 M determine pH - pOH - (OH-)

OpenStudy (sup_open~study):

can some one please help me thank you !!!

OpenStudy (sup_open~study):

@aaronq i need your help :)

OpenStudy (aaronq):

pH=-log[H3O+]

OpenStudy (aaronq):

then, pH+pOH=14 then pOH=-log[OH-]

OpenStudy (sup_open~study):

how do i do the -log(h30+) ???

OpenStudy (aaronq):

log(3.48x10^-8) then multiply by -1

OpenStudy (aaronq):

use your calculator

OpenStudy (sup_open~study):

can you show me the next step please :) ty

OpenStudy (aaronq):

you found pH?

OpenStudy (aaronq):

then: pH+pOH=14 then to find [OH-], pOH=-log[OH-]

OpenStudy (sup_open~study):

thanks man sorry for the late reply school ended :(

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