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you have to find the moles of acid and the moles of base, which will cancel, find the one that has more.
use: molarity=moles/L of solution and then to find the pH=-log[H3O+]
your thought process is correct, but you would have 0.001 moles OH- 0.002 moles H+ (because it's a diprotic acid, meaning 2 H+'s)
yeah, you need to divide by 2 and take into account the total volume when calculating the final pH
cool, thanks!
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