Question

If sin theta=(-3/5) and theta terminates in the fourth quadrant, find the exact value of tan 2theta

Answer 1

1. If the angle is in the Fourth Quadrant, then we know that...

sin(θ) < 0 and cos(θ) > 0.

Then...

cos(θ) = 4/5
sin(θ) = -3/5
tan(θ) = sin(θ)/cos(θ) = -3/4

Hence...

tan(2θ) = 2tan(θ)/(1 - tan²(θ))
= 2(-3/4)/(1 - (-3/4)²)
= -24/7

Answer 2

if that is right...I believe it is...we just learned this

Answer 3

Yeah it is, thanks!

Answer 4

No Problem :) glad i could help