Question

how do i calculate k using the nernst equation?

Answer 1

i think by K you meant the "equilibrium constant". is that what you are trying to find? it will also help me if you come up with a simple example of what you mean.

Answer 2

my E^o^ value is .32 n=6 E=0 and T=298

Answer 3

how do i rearrange the equation to find k

Answer 4

Gsoda is right we don't have a lot to work on... however we can solve for the equilibrium constant using Nernst equation and we find that:
\[\log(K)=\frac{ z(E_{r}^{\Theta}-E _{l}^{\Theta} }{ 0,0592 V }\]
At 25 °C.

Answer 5

my E^o^ value is .32 n=6 E=0 and T=298

Answer 6

E is the electromotive force?

Answer 7

e is the cell potential

Answer 8

And your standard cell potential you have donated "E^o^"?

Answer 9

yes

Answer 10

Hmmm
\[E=E ^{\Theta}-\frac{ RT }{ zF } \ln(K) \rightarrow E-E ^{\Theta}=\frac{ RT }{ ZF } \ln(K)\]
\[E-E ^{\Theta}=\frac{ RT }{ zF } \ln(K) \rightarrow \frac{ EzF }{ RT }-\frac{ E ^{\Theta}zF }{ RT }=\ln(K)\]
Take the exponential function to everything and we should be good?

Answer 11

im drawing a blank on how i find the ln k like to solve for the k value

Answer 12

logarithm rules

ln(K)=x

K=e^x

Answer 13

I am still not getting the right answer when I do the math

Answer 14

K=e^[E^0(nF/RT)]

Answer 15

did you use the right R?

Answer 16

8.314?

Answer 17

yep

Answer 18

faradays constant?

Answer 19

96486

Answer 20

got it thanks so much

Answer 21

sweet!