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Mathematics 4 Online
OpenStudy (anonymous):

Half-Life Un-decayed atoms Decayed Atoms What is this Toss# What is this Parents What is this Daughter 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0 Data Analysis: Answer this Analyze your data question: How many un-decayed atoms of an element will remain after 2.5 half-lives?

OpenStudy (anonymous):

@joannaxox3 @joyce153 @kevincourtes @heyheyhelpme help me please

OpenStudy (anonymous):

please help i will give you a medal

OpenStudy (anonymous):

idk bye?

OpenStudy (anonymous):

How many un-decayed atoms of an element will remain after 2.5 half-lives? this is the question

OpenStudy (anonymous):

@jen1511 @kymy_rose00 @LoveYou*69 @galacticwavesXX please help

OpenStudy (anonymous):

the data is confusing. What does each column represent?

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

tess# un-decay atoms decay atoms 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0

OpenStudy (anonymous):

please help me! i really need help

OpenStudy (anonymous):

@heathernelly @Kayy_Drizzyy @lala2 @o.Ohuh? @Ashleyisakitty

OpenStudy (anonymous):

i honestly dont know....i would need sometime to remember how to do half-lives from given data tables

OpenStudy (anonymous):

oh please someone else

OpenStudy (anonymous):

i willgive medal

OpenStudy (anonymous):

pleasseeeee

OpenStudy (anonymous):

what i am thinking you have to do is use the formula \[N(t)=N _{0}e^(kt)\] the problem is that we don't have anything in the data hat indicates time

OpenStudy (anonymous):

thats is e^kt idk why it came out like that

OpenStudy (anonymous):

are you sure you didnt leave out any givens that would help us?

OpenStudy (anonymous):

let me see

OpenStudy (anonymous):

Half-Life Un-decayed atoms Decayed Atoms What is this Toss# What is this Parents What is this Daughter 0 100 0 1 45 55 2 25 20 3 13 12 4 6 7 5 3 3 6 1 2 7 0 1 8 0 0 Data Analysis: Answer this Analyze your data question: How many un-decayed atoms of an element will remain after 2.5 half-lives? no that was all

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