Question

What is the pH of the following:

[OH]= 4.4x 10^-9M
[OH]= 2.4x 10^-2M
[H3O+]= 1.53X10^-2M

Answer 1

Formulas are
pH=-log[H3O+]
pOH=-log[OH]
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and relation of pH and pOH is
pH+pOH=14
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Use these as a guide

Answer 2

I'm unsure of how to type these into my calculator but, theoretically, if I were trying to find [OH]=4.4X10^-9M would I do -(4.4x10^-9) - 14?

Answer 3

Just type in
\[-\log(4.4 \times 10^{-9})\]

Answer 4

That will give you 8.3565

Answer 5

so I subtract that from 14 right? to get about 5.65?

Answer 6

Correct

Answer 7

And I do the same thing for [H3O+] right?

Answer 8

For that you don't have to, because
pH=-log[H3O+]

Answer 9

You don't have to minus 14

Answer 10

Its already in pH

Answer 11

Oh, okay. So my answer is whatever it is already.

Answer 12

Yes

Answer 13

Thank you so much!

Answer 14

Welcome :)