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Linear Algebra
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log3 (x+5) = log3 (2x+13)
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Subtract the right hand side from the left and you have\[\log_{3}(x+5) - \log_{3}(2x+13) = 0 \]
This simplifies to \[\log_{3}\frac{ x+5 }{ 2x+13 } = 0\]
i got 5
This means that \[\frac{ x+5 }{ 2x+13 } = 3^0 = 1\]
since the base is the same .. Then cancel the log and solve for x x+2=2x+13 Solve for x now
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Now you can solve. You should get x=-8.
@OakTree No need for that ...
@Eyad That's true, but it helps to demonstrate the reasoning instead of just stating that something is true.
oh wait, -8 is right, sryy
ok just set those equations equal to each other as x+5=2x+13 and then pull the terms with x to one side and the numbers to the other side so.. x= -8 right.. and thats it :)
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