-16x^4-32x^3-80^2 factoring
help asap please

Question

-16x^4-32x^3-80^2 factoring 
help asap please

anonymous · Answer

What common factors do you see?

anonymous · Answer

Let's not just toss out the answer, or we'll have ten more problems like this to do.

anonymous · Answer

i dont even know how that person did that, i need explanation

anonymous · Answer

oh shoot i meant 80x^2

texaschic101 · Answer

you need to find a common factor that will go into each of the numbers

anonymous · Answer

8x?

anonymous · Answer

i wasnt tryna be rude or start anything i was js

anonymous · Answer

nooooo wait16x?

texaschic101 · Answer

try -16x^2

anonymous · Answer

You can always divide out a factor and see whether there still is one. What trinomial do you get after removing the common factors?

anonymous · Answer

grr, your right,

anonymous · Answer

x^2-16x-5?

anonymous · Answer

i mean x^2+2x-5

anonymous · Answer

ok

anonymous · Answer

oh ok, ya the first one confused me
but yah

anonymous · Answer

yah

anonymous · Answer

nope u lost me, the drawing confused me

anonymous · Answer

May I step in?

anonymous · Answer

sure

anonymous · Answer

$$-16x^4-32x^3-80x^2=-16(x^2+2x^3+5)$$
Multiply it out to test it. Then tell me if you follow so far.

anonymous · Answer

i follow

anonymous · Answer

i give up

anonymous · Answer

well i really need to know this its just confusing with different people telling me different stuff

anonymous · Answer

I left out the x^2. Let me fix it.

anonymous · Answer

$$-16x^4-32x^3-80x^2=-16x^2(x^2+2x+5)$$

anonymous · Answer

@numb3r1 i follow now

anonymous · Answer

@Loser66 i feel like you are blowing things out of proportion thank you for ur help

anonymous · Answer

OK, so keep the 16x^2 off to the side. Can the trinomial be factored, either manually or with the quadratic formula?