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Mathematics 8 Online
OpenStudy (anonymous):

Two men go to the store for 6 minutes between 1:00 and 1:30. What's the probability that they will meet?

OpenStudy (texaschic101):

6/30 = 1/5 You might need to get a second opinion on this.

OpenStudy (anonymous):

Everyone gives up?

OpenStudy (jack1):

so there are 25 "6 minute chunks" of time between 1:00 and 1:30

OpenStudy (anonymous):

mhm

OpenStudy (jack1):

and the question is what are the odds that any one of these minutes will overlap with the other persons'?

OpenStudy (anonymous):

mhm

OpenStudy (anonymous):

This is more of a challenge for you guys. I've already solved the problem lol.

OpenStudy (anonymous):

It's almost like a competition to see who does it first.

OpenStudy (jack1):

bail

OpenStudy (texaschic101):

how is there 25 six minutes chunks in 30 minutes ?

OpenStudy (texaschic101):

@Mertsj ....can you please help

OpenStudy (texaschic101):

@Zale101 ...can you help ?

OpenStudy (texaschic101):

I give up...I don't know

OpenStudy (anonymous):

should be 9/24. that's what i got.

OpenStudy (anonymous):

what you do here is you develop an inequality and consider the two men as x and y. graph the solution to each inequality based on the time intervals and find the intersection. get the area of the region within the intersection and that's your answer.

OpenStudy (texaschic101):

I didn't even think of that.....your good

OpenStudy (jack1):

@texaschic101 how is there 25 six minutes chunks in 30 minutes ? was assuming it was 1:00 - 1:30 inclusive so 0-5 1-6 2-7... etc

OpenStudy (jack1):

@genius12 sorry could you explain that a little bit, im intrigued?

OpenStudy (jack1):

the how did u get equations for each part

OpenStudy (anonymous):

So basically you make a graph where the x-axis and y-axis both go from 1:00 to 1:30 or 0-30 in minutes. You draw the the line y = x because along this line is when they are at the store at the same time. The two cases, or the inequalities will be y - x < 6 or x - y < 6, where x and y is each man. Graph the two inequalities and find the intersection. Find the area of of the region enclosed by the intersection and that gives you the number of times they can meet. We also know that this 30min by 30min first quadrant gives us 900 possibilities (30^2) in total, so the area of the region of enclosed by intersection will be the numerator of the probability and 900 will be the denominator. The reduced form of this fraction will be the answer. @Jack1

OpenStudy (jack1):

thanks @genius12

OpenStudy (anonymous):

http://i40.tinypic.com/21l8kef.png @Jack1 This is the graphed solution and the purple region in the first quadrant.

OpenStudy (jack1):

gotcha, much better now, thanks @genius12

OpenStudy (anonymous):

np

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