Question

A committee of two persons is selected from two men and two women.
What is the probability that the committee will have (a) no man? (b) one man? (c) two
men?

Answer 1

@oldrin.bataku

Answer 2

Consider the possibilities; here, we have M,N be our men, and W,X be our women.

MN, MW, MX, WN, WX, XN

Now, how many have no men? Well, we have only WX, so its probability is \(1/6\).

How many have one man? We count MW, MX, WN, XN, so our probability is \(4/6\).

Lastly, we're left with only one occurrence of two men, MN, so its probability is \(1/6\). Notice that two men is the same as no women, hence its probability is equal to that of having no men :-)

Answer 3

@kropot72 we are sampling w/o replacement so your computations are off.

Answer 4

not to mention our committee is only 2 people. Try again.