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find the indefinite integral (3x-7)^-6 dx
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That I have no idea how to even start! Everything I try I get the wrong answer
Okay we can use power rule for integration here directly, \[\int\limits x^n dx=\frac{x^{n+1}}{n+1}\]
Followed by chain rule \[\int\limits (3x-7)^{-6} dx \\ \\ =\frac{(3x-7)^{-5}}{-5(3)}+c\] The 3 from the denominator comes from chain rule, which means you'll differentiate (3x-7)
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