Question

Show work & Help me! :D Medal will be rewarded! :D I need help on 60 & 61 on page 529. Help me get started on each problem please! :D Here's the link: http://www.mrlarkins.com/algebra2/docs/chap10.pdf

Answer 1

The answer on #59 is \[y = 3.93(1.35)^x\]

Answer 2

For question 60, use the exponential function as been typed above and insert the x value as the number of decades since 1790. For example:
For 1820: the number of decades since 1790 is equal to : (1820 -1790) / 10. From this answer which is 3, sub x = 3 and the y value is the population during that specific year (1820). The other years in the question , 1840 and 1860 work in the same way.

Answer 3

would it be: \[y = 3.93(1.35)^{1820}\]

Answer 4

Insert the 3 into where x is

Answer 5

No, the reason for this is that x is not the year such as 1820 but rather the number of decades since 1790.

Answer 6

Yes, insert the 3 due to the reason mentioned above where 3 is the number of decades from 1790 to 1820.

Answer 7

I have a calculator what would I look for in the table

Answer 8

Table?

Answer 9

do you know what I mean?

Answer 10

no?

Answer 11

Start me on #61

Answer 12

For 1820, it says 9.6693

Answer 13

would it be okay to put the whole thing?

Answer 14

that answer is correct as it is expressed in millions.
Sorry, what do you mean the whole things, the expression into the calculator?

Answer 15

How would I compare my answers for #60 to the actual population?
My Answers:
9.67 ----> 9.6693 <--- the 9 makes the 6 go up to a seven
17.62 ----> 17.622 <---- the 2 makes the 2 stay the same
32.12 ----> 32.117 <--- The 7 makes the 1 go up to a 2

Answer 16

@Hyper

Answer 17

When the questions includes a compare, it mean how similar or dissimilar are the quantities. For the first answer, it is very similar will less than a 100,000 population difference. The same applies to the others and it just goes to show how accurate the exponential function is which was determined in #59 to the actual population as a calculator.