Find the roots of the polynomial equation.
x^2 + 24 = 11x

A. 12, 2

B. 3, 8

C. –8, –3

D. –12, –2

Question

Find the roots of the polynomial equation.
x^2 + 24 = 11x

A. 12, 2

B. 3, 8

C. –8, –3

D. –12, –2

unklerhaukus · Answer

move all the terms to the left hand side, by talking away 11x form both sides

unklerhaukus · Answer

$$x^2-11x+24=0$$
then you see to factorise into this form 
$$(x+x_1)(x+x_2)=0$$

you need to find $x_1,x_2$ 

you need $$x_1+x_2=-11\x_1x_2=24$$

anonymous · Answer

to get the roots, this means get the 'answers' if you like or to be more precise get the values that give 0 when you substitute them into an equation. for equations with xsquared as the highest power we get 2 answers, for equations with x-cubed we get 3 answers(roots) and so on. to get the roots of the equation we usually use factors to get them. firstly if the equations has an x-squared or higher then everything moves to one side so you have it all =0. this gives you:
$$x^2-11x+24=0$$
now you get the factors of this and out them both =0 to get your two x values which are your roots.
i'll leave you to get the factors then!

anonymous · Answer

wich one is it

anonymous · Answer

hello???

unklerhaukus · Answer

do you know factors of 24?