Question

Somebody check my answer please!

Answer 1

Al LOL

Answer 2

You sure? why?

Answer 3

the metal which gets oxidised is reducing agent in ur case al metal got oxidised to Al+3 sooo

Answer 4

the reducing agent CAN'T be a product. ever.

Answer 5

yaaa LOL it cant be a product

Answer 6

Wait which side is the products?

Answer 7

how to figure out this one then?

Answer 8

LOL right side of the arrow are products and reactants are left of the arrow

Answer 9

can you tell me oxidation of carbon in reactant and product side

Answer 10

the oxidizing agent is always the reactant that causes the OTHER GUY to be oxidized.

oxidation is the LOSS of electrons.

Figure out which reactant loses electrons. That's the one that's oxidized. The OTHER reactant is the oxidizing agent.

it works the same way for the reducing agent

Answer 11

hey its not " other guy" LOL its another element or atom or molecule

Answer 12

true, but the meaning is the same

Answer 13

so.. CS2 is the oxidizing agent? @chmvijay

Answer 14

NOO

Answer 15

the oxidizing agent CANNOT be a product

Answer 16

Then its C!

Answer 17

it is the C. the oxidizing agent is the reactant that GETS reduced

Answer 18

thank you. what about this one?

Answer 19

basic solution mean what ions will be there H+ or OH-

Answer 20

thank you. Am I right on this one?

Answer 21

@chmvijay

Answer 22

why none LOL

Answer 23

because look on each side. 2 time 2 4 then on the other side its the same.

Answer 24

@chmvijay

Answer 25

that is not electron LOL

Answer 26

then im confused?

Answer 27

so 2? @chmvijay

Answer 28

yaaaaa

Answer 29

last two can you help me with ? @chmvijay

Answer 30

OK LOL iam helping for all ur stuff today

Answer 31

at anode what reaction take place :)

Answer 32

a reduction ? @chmvijay

Answer 33

LOL noooo

Answer 34

what type does then?

Answer 35

@chmvijay

Answer 36

oxidation occurs ! @chmvijay

Answer 37

then it s A right

Answer 38

yes what about the second question?

Answer 39

TRUE

Answer 40

thank you so much, @chmvijay

Answer 41

ur welcome LOL:)