Suppose you choose a marble from a bag containing 3 red marbles, 5 white marbles, and 4 blue marbles. You return the first marble to the bag and then choose again. Find P(red and blue)
help me bro
First you need to find the individual probabilities of drawing a red marble and a blue marble. \[P(red)=\frac{number\ of\ red\ marbles}{toal\ number\ of\ marbles}\] Can you do that?
yeahhh bruh thanks
What is your result?
7/12
Not really. \[P(red)=\frac{number\ of\ red\ marbles}{total\ number\ of\ marbles}=\frac{3}{12}\] Now you need to find the probability of drawing a blue marble which is \[P(blue)=\frac{number\ of\ blue\ marbles}{total\ number\ of\ marbles}\] The probability P(red and blue) is given by \[P(red)\times P(blue)=you\ can\ calculate\]
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