Question

divide. 3n^2-n/n^2-1 divided by n^2/n+1

Answer 1

\[\frac{3n^2-n}{n^2-1}\div \frac{n^2}{n+1}\]

Answer 2

First change it to a multiplication problem by inverting the second fraction.

Answer 3

wat is inverting is thst like the reciprocal

Answer 4

yes. Change it to its reciprocal.

Answer 5

And then factor the numerator and denominator of the first fraction.

Answer 6

then u get 3 divided by n+1 over n^2?

Answer 7

\[\frac{n(3n-1)}{(n-1)(n+1)}\times \frac{n+1}{n^2}=\frac{3n-1}{n(n-1)}\]

Answer 8

then u get 3 over n as the answer or just 3

Answer 9

Did you read what I wrote?

Answer 10

That fraction will not reduce any further.

Answer 11

oh okay thank you

Answer 12

yw