Please check my answer! write the terms of the series and find the sum. \[\sum_{k=1}^{4} (k+9)^{2}\] N =4 534
just expand the series 100, 121....
yes - your answer is correct @marcybaby :)
wait - what you just wote does not agree with what you wrote in the question
woooohooo!! I'm killing myself over here!
how u got that terms?
in your question you wrote an answer of 534 - correct?
but what about the terms?
how did you get that answer?
I'm gonna need a new brain after this!
no need to panic :)
just explain how you got your answer of 534
1/6 (541 N + 57 N^2 + 2 N^3)
where did that expression come from?
HA!!! i have NO idea!
I dont know how the hell I got that answer anymore!
ok, lets take it one step at a time. you are told that the k'th term is equa to \((k+9)^2\). so, given that, what do you think will be the first first (i.e. when k=1) ?
*first term
i'm so lost now! :(
ok, the sum is given as:\[\sum_{k=1}^{4} (k+9)^{2}\]agreed?
yes
the \(\sum\) symbol means "sum this expression" and the "k=1" at the bottom of this and "4" at its top mean that "k" should take on the values from 1 to 4. agreed?
yes.
good - this is basically a short hand way of writing the sum. so, if we expand the sum, we will get:\[\sum_{k=1}^{4} (k+9)^{2}=(1+9)^2+(2+9)^2+(3+9)^2+(4+9)^2\]can you see how that follows?
I do!
gr8! so all you need to do now is work out the numbers on the right and bingo! you should get to your answer. :)
so it shoule be (10)^2? or (1)^2&(9)^2?
you evaluate the expression inside the braces first, e.g.:\[(1+9)^2=(10)^2=100\]
okay! 100, 121, 144, 169
perfect! now just add these up...
534
thats it! great work! :)
see - no new brain required :)
duh! LOL i did that you know. but i thought i had it all wrong
thank you so much!!!! i need a drink!
learn to trust yourself :)
and you're welcome :)
xoxo
go on - you deserve that drink now...
I wish! i have more to do.
hehe - no worries, I'm sure the drinks will still be there when you've finished! :)
Ha! thanks a million! first drink is dedicated to you! :)
cheers to that! :)
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