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Find the intervals on which the function is continuous y =(x + 3)/(x^2 - 5x + 6)
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$$ \cfrac{x+3}{x^2-5x+6} \implies \cfrac{x+3}{(x-3)(x-2)} $$ bearing in mind the denominator cannot be "0", or the fraction becomes "undefined", what values "x" must NOT take?
what about
its multiple choice and this are the answers
A) discontinuous only when x = -3 or x = 2 B) discontinuous only when x = 2 or x = 3 C) discontinuous only when x = -2 or x = 3 D) discontinuous only when x = 2
which one
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ahemm, which one do you think?
imnot sure
jodie0001 has explained perfectly. @iplayffxiv You should read what he wrote and use that to determine your answer. Even if you get the answer wrong, it's better to give a wrong answer than nothing at all. ;)
is it b?
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