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Let f(x) be a polynomial with integer coefficients. Suppose that there are distinct integer a1, a2, a3, a4, sich that f(a1) = f(a2) = f(a3) = f(a4) = 3, show that there does not exist any integer b with f(b) = 14
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f is of the form f(x)=q(x)(x-a1)(x-a2)(x-a3)(x-a4)+3
if f(b)=14 then q(b)(b-a1)(b-a2)(b-a3)(b-a4)+3=14 q(b)(b-a1)(b-a2)(b-a3)(b-a4)=11 but 11 is prime, thus ...
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