Question

4x²+9y²=36; solve for y, then differentiate to get y' in terms of x

How do I even begin ?

Answer 1

Well , first of all transpose \(4x^2\) to Right Hand side.

Can you do that ?

Answer 2

YES can YOU!

Answer 3

Yup

Answer 4

ok then will you!

Answer 5

mr BURHAN

Answer 6

Please do that burhan ... for us

Answer 7

haha ur name is awesome

Answer 8

okay haha

Answer 9

You will get : \(9x^2 = 36-4x^2\) , right?

Answer 10

\[\huge 36-9y^3=4x^2\]

Answer 11

\(9y^2 = 36-4x^2\)

I meant this. @burhan101 from where did \(9y^3\) come from, in the question it is \(9y^2\)

Answer 12

Typo *

Answer 13

haha i was laughing, one guy turns the y to x the other makes it y^3 lol

Answer 14

ok. now , divide both sides by 9 :

\(9y^2 = 36-4x^2\)

\(\cfrac{9y^2}{9} = \cfrac{36-4x^2}{9}\)

\(\cfrac{\cancel{9} y^2}{\cancel{9}} = \cfrac{36-4x^2}{9} \)

\(y^2 =\cfrac{36-4x^2}{9} \)

Answer 15

so we're solving for y

Answer 16

Right.

Answer 17

I have \(y^2\) , now take square root both sides to get \(y\) in terms of x.

Can you do that ?