||x|| refers to the greatest integer function lim x-> 3 (from the left) of.. (||x||-x^2)= ?
when x->3 from left (also called \(3^-\)) x is very very near to 3, but LESS than 3 so, what you think will be the value of ||x||, when x= \(3^-\)
and you know what is greatest integer function, right ?
nope :x That's the reason I posted this question up here. not sure what that means xD
ohhh.. greatest integer function is also called floor function, it is the largest integer not greater than x. so, ||+5.4|| will 5 because its not greater than 5.4 and its largest among, 5,4,3,2,....
got that ?
Mmmm gotcha so I'd subsitute 2 instead?
you got it :) ||\(3^-\)|| = 2
so the value of limit will be ?
-7 :b
correct :)
Thanks a bunch. Quick question, for another question... lim x->0 from the left of (x-2sqrt(x)+1)/(sqrt(x)-1) = ? I simplified to get sqrt(x) -1 = ? but what happens since when substituting x it's taking the radical of a negative number? should I just count it as zero? Does the limit not exist?
after you are left with sqrt x-1 you can directly plug in x=0
don't I need to plug in the -.0001 though? I mean just plugging in zero makes sense but thought it'd go against the steps you're meant to take
while taking the limit, we always plug in that number, like if x->+4 from right, we won't plug in 4.00001, we will plug in 4 only. +4 from right means values near to and greater than 4, yes, but while evaluating the limit, we just plug in 4.
and interpretation of your question will be as x tends to 0 from left (x-2sqrt(x)+1)/(sqrt(x)- 1) tends to -1
gotcha
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