Question

Help please!

Answer 1

@.Sam.

Answer 2

Vapour pressure of Methyl alcohol and ethyl alcohol solutions is represented by
\(P=115_(x_a)+140\) where \(x_a\) is the mole fraction of Methyl alcohol.The value of
\[\LARGE \lim_{x_a \rightarrow 0} \frac{{P_b}^0}{x_B} ~=?\]

Answer 3

@Preetha

Answer 4

Just a random attempt:
\[\Large P=115x_a+140=P_a \times X_A + P_b \times X_B\]
\[\Large \frac{115x_a}{(x_B)^2}+\frac{140}{(x_B)^2}=\frac{P_a \times X_A}{(x_B)^2} +\frac{(P_B)^0}{X_B}\]
I divided by X_B squared now I think xa terms will be 0 due to the limit

Answer 5

140/Xb^2=Pb/Xb is what I'm left with,dunno if im going in the right direction

Answer 6

\[\Large X_B=\frac{\frac{M_{Ethanol}}{46}}{\frac{M_{Methaol}}{32}}\]
I don't think neglecting Xb in denominator would cause much effect,approximately I need this value not sure about masses now.

Answer 7

final ans = 140 ? is it? :|

Answer 8

yes nvm

Answer 9

hmm

Answer 10

?

Answer 11

what? it was incorrect right? :O

Answer 12

ohh :|
let me show my work

Answer 13

I have options though
255
115
135
140

Answer 14

P = 115 xa + 140 = Pa xa + Pb (1- xa) = xa ( Pa - Pb) + Pb

on comparison, Pb = 140 and Pa =255

when xa -> 0 , xb -> 1
so my guess would be ans is 140