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Chemistry 15 Online
OpenStudy (freethinker):

find the molecular formula of a given empirical formula if the molar mass was determined to be 453 g/mol

OpenStudy (freethinker):

\[C_8H_9NO_2\]

OpenStudy (anonymous):

Is that a H9 or H3?

OpenStudy (freethinker):

9

OpenStudy (anonymous):

C-12g/mol H-1g/mol N-14g/mol O-16g/mol molar mass of C: 12x8=96g/mol molar mass of H: 1x9g/mol=9g/mol N: 14g/mol O: 16x2=32g/mol 96+9+14+32=151g/mol 453g/mol/151g/mol=3 8x3=24 3x9=27 1x3=3 2x3=6 Therefore the molecular formula= C24H27H3O6 (:

OpenStudy (anonymous):

Note the numbers in the molecular formula I typed out are subscripts.

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