Help with exponential equation:

Help with exponential equations:

After solve the following exponential equation, x takes the form of 4^n
x^(x^0.5) = 0.5^(1/2)

What is teh value of n?
Any idea , thanks.

Question

Help with exponential equation:

Help with exponential equations:

After solve the following exponential equation, x takes the form of 4^n
x^(x^0.5) = 0.5^(1/2)

What is teh value of n?
Any idea , thanks.

anonymous · Answer

The equation is the following:
|dw:1368265282258:dw|

xanthe · Answer

Sorry bt wheres the unknown n in the equation?

anonymous · Answer

It says, " x takes the form of 4^n "
So we must solve for x and then for n.

xanthe · Answer

Sorry dude idk:(

xanthe · Answer

Bt is it a logarithm or calculas qn?

anonymous · Answer

I think we're not supposed to use logarithms, i tried that and was useless.

gorv · Answer

take log both sides
x^0.5(logx)=(1/2)log0.5

geerky42 · Answer

I don't think it is possible to solve it algebraically. On calculator, graph $y = x^{x^{0.5}}$ and $y = \sqrt{0.5}$ and then find the value of x where they intersect. (there are two intersections)

Hope this help.