A line has a slope of 1 and passes through the point (6, 3). What is its equation in slope-intercept form?
Well... if you have a slope m and the line passes through the point (a,b) then the line has the equation... \[\huge y = \color{blue}m(x-a) + b\]
Then you would have y=1x-6+3
Actually, yes :) You can do away with the 1... And you'll have...?
y=x-6+3
Come on, you can still do stuff with that... \[\large y = x-6+3\\ \large y = x \boxed{\color{red}{-6+3}}\]
y=x-3
Yes, perfect :)
Thank you so much:)
No problem :) I'm TJ, welcome to OpenStudy... Stick around, see if you can help with some other guys with questions :D
okay one last question The points (0, 8) and (-20, 12) fall on a particular line. What is its equation in slope-intercept form?
Okay, you need a slope here... If you have two points, (a,b) and (c,d) the slope is given by this formula... \[\Large m = \frac{d-b}{c-a}\] So, can you get the slope?
1/-5
okay... \[\Large m = -\frac15\] That's very good... Now you use the formula again... we have a slope now... \[\LARGE y = m(x-a) + b\] As for your point, you can use any one of the two points you have been given, it doesn't matter...
okay so \[y=1/-5(x-0)+8\]
Yeah, careful...I know you have the correct idea... let me just rewrite it for you... \[\Large y = -\frac15(x-0) + 8\]
So the final product would be \[y=-1/5x-8\]
I mean +8
Okay, I just hope you meant this... \[\LARGE y = -\frac15x + 8 \] It seems you have it down, good job :)
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